A small particle has charge -6.90 micro-Coulombs and mass 1.00×10-4 kg . It moves from point A, where the electric potential is VA= 280 V , to point B, where the electric potential is VB= 930 V; note that this is greater than the potential at point A. The electric force is the only force acting on the particle. The particle has a speed of 5.60 m/s at point A.

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Since there is no other force applied to the particle but only electricforce, the total energy must conserved (total energy at point A equals to the total energy at point B).

EA = EB

EA = (1/2)*m*Va^2 + q*VA
EB = (1/2)*m*Vb^2 + q*VB,

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