Explore BrainMass
Share

# Elasticity

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

A lead brick with the dimensions shown in the figure below (6.0 cm left to right, 5.0 cm front to back and 2.0 cm top to bottom) rests on a rough, solid surface. A force of F = 2300 N is applied as indicated, with θ = 29°.

(a) Find the change in height of the brick.
_____m
(b) Find the amount of shear deformation.
______m

https://brainmass.com/physics/applied-physics/force-change-height-amount-shear-deformation-255564

#### Solution Preview

F=2300 N Fsinθ = 2300xsin29O = 1115 N

Θ=29O
Fcosθ = 2300xcos29O
=2012 N l = 0.06m, b = 0.05m, h = 0.02m

Force F can be resolved into horizontal and vertical components, Fcosθ and Fsinθ respectively.

The vertical component causes compression of the lead brick and the horizontal ...

#### Solution Summary

The expert finds the force and change in height and amount of shear deformation. A step by step solution provided.

\$2.19