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# Displacement of fluids when mass is submerged

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1. A mass is hung on a scale and while hanging the mass is submerged in water. The scale read .45 kg when submerged. When the mass is submerged the water displaced is 100 cm^3. What is the magnitude of the mass?

2. A car with windows closed floats in water when 50% submerged. If 1 m^3 of water seeps into the car it becomes totally submerged. What is the mass of the car?

https://brainmass.com/physics/applied-physics/displacement-fluids-mass-submerged-227851

## SOLUTION This solution is FREE courtesy of BrainMass!

1. 0.45 Kg = 450 g

Weight in water(apparent weight) = actual weight - weight of water displaced(loss in weight)
450 g = M - 100 g ... ( 100 cm^3 of water weighs 100g )
M = 450 + 100
= 550 g
= 0.55 Kg
The mass is 0.55 Kg.

2. Floating bodies displace their own weight of liquid.

Mass of car = Mass of water displaced
= {50% of V}*density of water ... ( Volume of car V )
= (V/2)*1000
= 500 V Kg ............ (1)

Mass of car + mass of water that seeped in = weight of water displaced by the car

Mass of car + mass of water that seeped in = V*1000 ..... (V*1000 Kg is mass of water displaced)
(applying again law of flotation i.e. floating body displaces its own weight of liquid )

500V + 1000 = 1000V .... (1m^3 of water weighs 1000Kg) ....... {mass of car 500 V , from (1) }
1000V - 500V = 1000
500V = 1000
V = 2 m^3
Volume of car = 2 m^3

Mass of car = 500 V ............. {from (1)}
= 500*2
= 1000 Kg

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!