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Constant acceleration and maximum height of a model rocket launched straight upward

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"A model rocket is launched straight upward from the ground with an initial speed of 53.3 m/s. It rises with a constant upward acceleration of 1.86 m/s^2 until its engines stop at an altitude of 161 m. What is the maximum height reached by the rocket?"

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The solution clearly explains the problem and provides formulas and calculations to arrive at the answer.

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Solution. We can think about this problem in the following way. First, the rocket can go upward with a constant acceleration a=1.86m/s^2 until its engines stop at an altitude of 161m. We can compute the time T it takes. Then, its engines stop and the rocket will decrease its speed to zero because of the gravity. When its speed ...

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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