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Jet Fighter Circular Acceleration in Vertical Plane

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A jet fighter can withstand a max acceleration of 9g's; The plane is pointed vertically downward at Mach 3 and will be pulled from the dive in a circular manuver (befoe crashing).

a. Where does max acceleration occur ?

b. What is the minimum radius the pilot can take?

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Solution Summary

The expert examines a jet fighter circular acceleration in vertical planes. The mac acceleration which occurs is determined as well as the minimum radius the pilot can take.

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The max acceleration occurs at the bottom point of the circle (see figure attached)

The force with which the seat pushes the pilot up at this point is found from the 2nd law of Newton,
ma = F - mg,

where a is the centripetal acceleration (if you like a variety of explanations on what is centripetal acceleration and force, take a look in the internet; an example of a nice link is http://hyperphysics.phy-astr.gsu.edu/HBASE/cf.html),

a = V^2/R

where m is the mass of the pilot, V is the speed of the plane and R is the radius of ...

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