Circular Motion: Centripetal Acceleration and Minimum Force
Please identify all variables used.
1) An engine flywheel initially spinning 2000 rpm has an angular acceleration of -10 rad/s2 as it slows down. How long does it take for the flywheel to turn through 100 revolutions? How long does it take to stop?
2) A 50 kg child stand at the rim of a merry go round with a radius of 2.00 m, rotating with an angular speed of 3.00 rad/s
a) What is the child's centripetal acceleration?
b) What is the minimum force between her feet and the floor of the carousel that is required to keep her feet in the circular path?
c) what minimum coefficeint of static friction is required? Is the answer reasonable? In other words, is she likely to stay on the merry go round?
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The equations of motion of angular motion are analogous to these apply to linear motion, only instead of distance we measure radians. Instead of linear velocity ...
Solution Summary
This solution provides calculations involving circular motion. The centripetal acceleration and minimum force is determined.
... the centripetal force required for the orbital motion of the ... and a half laps around a circular track in ... a rim of the wheel has a centripetal acceleration of 1.2 ...
... 8.94 m/s, = 0.8 In circular motion, the friction ... tires and the road surface provides the centripetal force. ... 2. The acceleration of gravity on the surface ...
... as the centripetal force which produces centripetal acceleration which is ... enough to keep it in a circular path with ... of rest or uniform rotational motion of a ...
... the loop to keep the block on a circular path ... not to fall we require that the centrifugal acceleration equals that ... When the block starts its motion it has only ...
... Solution: Centripetal force required for circular motion of the ... The roughly spherical comet has a radius of 2.7 km, and the acceleration due to gravity on ...
... calculate the average speed of the Earth with respect to the Sun; c) calculate the radial acceleration of the ...Centripetal force for circular motion of the ...
... T = centripetal force - mg (min). 4. Tangential acceleration is zero in UNIFORM circular motion 5. Radial acceleration (acting towards the radius) is not ...
... the child and the wall is 0.400, with what minimum speed is ... 2. The centripetal acceleration is. ... 6. The period of the circular motion is T = 1 /2 = 0.5 seconds ...
... In the case of circular motion, your acceleration, at least in ... The magnitude of centripetal acceleration is mv^2 ... would that change the equation of motion I just ...
