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# Angular Acceleration of a Ladder

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At a given instant the top B of the ladder has an acceleration Ab= 2ft/s^2 and a velocity of Vb=4ft/s, both acting downward. Determine the acceleration of the bottom A of the ladder, and the ladder's angular acceleration at this instant (see attachment for diagram).

#### Solution Preview

The coordinate of point B is (y_B)(t). The coordinate of point A is (x_A)(t).

The velocity of point B is therefore: v_B = y_B (using dot ...

#### Solution Summary

The solution is attached in two files. The files are identical in content, only differ in format. The first is in MS Word XP Format, while the other is in Adobe pdf format. Therefore you can choose the format that is most suitable to you. We use here the derivative of a multiplication of functions:
(f*g)' = f'g + fg'.

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