Sketch the surface of a spheroid inside a parabaloid and evaluate the surface integral.
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The surface S is that part of the spheroid
....
which lies inside the paraboloid az = x2 + y2; here a is a constant. Sketch the surface S and the paraboloid by drawing their intersections with the plane y = 0.
Show that Z Z
.....
where R is a region of the (x; y) plane you should find, and hence evaluate the surface integral (using plane polar coordinates in the plane integral).
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The surface of a spheroid inside a parabaloid is setched and a surface integral is evaluated. The solution is detailed and well presented.
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