Tourism is one consideration for a start up company in the Caribbean. A survey of 1,233 visits to the Caribbean last year revealed that 110 visited a small cafe during their visit. Bob claims that 10% of the tourists will include a visit to a cafe.
Use a 0.05 significance level to test his claim. Would it be wise for him to use that claim in trying to convince management to increase their advertising spending to travel agents? Explain.© BrainMass Inc. brainmass.com March 4, 2021, 6:26 pm ad1c9bdddf
In this case the sample probability is p=110/1233=0.0892
The sample error is given by
S = Sqrt[(p)(1 - p)/n] =Sqrt[(0.0892)(1-0.0892)/1233]=0.008
then compute t = (p-10%)/ S = (0.10 - 0.0892) / 0.008 = 1.35
Since this is ...
The solution gives the formulas and solves the problem, but then offers a solution which would be better suited for the facts.