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Probability

Two separate questions below:

A.) A bin contains 20 fuses of which 5 will be defective. If 2 fuses are selected at random without replacement, what is the probability that at most, one is defective?(Please show equation)

B.) From a group of 5 men and 6 women, how many committees of size 3 are possible with 2 men and one women if a certain man must be on the committee?
(Please show equation)

Solution Preview

A) Prob of Defective = Number defective / Total = 5/20 =.25
If two fuses are selected at random without replacement , Prob of getting at most 1 defective = Prob ( 0 defective) + Prob ...

Solution Summary

A.) A bin contains 20 fuses of which 5 will be defective. If 2 fuses are selected at random without replacement, what is the probability that at most, one is defective?(Please show equation)

B.) From a group of 5 men and 6 women, how many committees of size 3 are possible with 2 men and one women if a certain man must be on the committee?
(Please show equation)

$2.19