Hamburger Probability
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Because of a recent incident in which a number of people became ill after eating undercooked hamburger meat, intensive interest has centered around the cooking time for hamburger patties. In the past, the cooking time at a local fast food firm has been found to be uniformly distributed between 4 and 5 minutes.
a) A TV reporter, Jane Greer, came to the restaurant and observed the cooking time of her meat patty. What is the probability that her burger was cooked less than 4.2 minutes?
b) If in a separate visit by Jane with four other reporters, each ordered one hamburger, what is the probability that at least two of the patties will be cooked less than 4.2 minutes?
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Solution Summary
The recent incident in which a number of people became ill after eating undercooked hamburger meat, intensive interest has centered around the cooking time for hamburger patties. In the past, the cooking time at a local fast food firm has been found to be uniformly distributed between 4 and 5 minutes.
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Solution.
a) We denote the cooking time at a local fast food firm by X. By the hypothesis, X is a random variable and uniformly distributed between 4 and 5 minutes. We denote simply by ...
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Recent Feedback
- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
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