Last year a trial survey found that 65% of houses in a town had a computer. A follow up survey wants to find the actual number of houses with a computer to within 3% with a 95% confidence interval. How many houses should it survey?
p = 65% = 0.65, q = 1 - p = 0.35; z- score corresponding to 95% confidence level is ...
A Complete, Neat and Step-by-step Solution is provided.