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# Random Sample

PERSISTANT LOW HEMOCRIT IN ALL THE ELDERLY PATIENTS IN A NURSING HOME F .31, WITH A NORMAL OF .41. AN INTERVENTION PROGRAM OF AN IRON SUPPLEMENT WAS INITIATED TO SEE IF THE HEMOCRIT WOULD INCREASE.
A RANDOM SAMPLE OF 100 PATIENTS SHOWED THAT 60 PATIENTS NOW HAD ELEVATED LEVELS OF HEMOCRIT OF .41.
CAN WE CONCLUDE AT ALPHA= 0.05 THAT THE INTERVENTION WAS A SUCCESS?
a. what is the error value.
b. state the null and alternative hypotheses
c. define the test statistic
d. develope the decision rule.
e.compute the test statistic
f. state the conclusion.

#### Solution Preview

HI there,
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<br>First we sould clarify the problem.
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<br>Normally - the frequency of hemocrit is 0.31 - therfore - 100 people, there should be 31 who have hemocrit. (Normal hemocrit levels are 0.41).
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<br>Now an experiment is done to test if giving iron will increase the hemocrit level of seniors.
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<br>SO the expected number of seniors who have elevated hemocrit is 31/100
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<br>When 100 seniors were given iron, now we see that 60 had elevated hemocrit.
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<br>In this problem, we are going to compute a test statistic called the T-test. BUT we have a major assumption here. In this problem, the stanard ...

#### Solution Summary

The solution addresses a PERSISTANT LOW HEMOCRIT IN ALL THE ELDERLY PATIENTS IN A NURSING HOME F .31, WITH A NORMAL OF .41. AN INTERVENTION PROGRAM OF AN IRON SUPPLEMENT WAS INITIATED TO SEE IF THE HEMOCRIT WOULD INCREASE.
A RANDOM SAMPLE OF 100 PATIENTS SHOWED THAT 60 PATIENTS NOW HAD ELEVATED LEVELS OF HEMOCRIT OF .41.
CAN WE CONCLUDE AT ALPHA= 0.05 THAT THE INTERVENTION WAS A SUCCESS?
a. what is the error value.
b. state the null and alternative hypotheses
c. define the test statistic
d. develope the decision rule.
e.compute the test statistic
f. state the conclusion.

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