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Applying statistics for smokers and nonsmokers

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Dr. Z at the Clinic wishes to see whether the pulse rates of smokers are higher than the pulse rates of nonsmokers. Samples of 100 smokers and 100 nonsmokers are selected. The results are shown here. Can Dr. Z conclude, at alpha = 0.05, that the smokers have higher pulse rates than nonsmokers? Assume the samples come from a normal population. Use Minitab to help solve the problem if using statistical software.

Smokers
Sample mean = 90
Standard deviation = 5
Sample size = 100

Nonsmokers
Sample mean = 88
Standard deviation = 6
Sample size = 100

State the hypothesis:

Find the critical value:

Identify and Compute the test value:

Make a decision:

Interpret the results within the context of the problem:

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Solution Summary

The solution applies statistics for smokers and non-smokers using minitab to determine is smokers have higher pulse rates.

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Dr. Z at the Clinic wishes to see whether the pulse rates of smokers are higher than the pulse rates of nonsmokers. Samples of 100 smokers and 100 nonsmokers are selected. The results are shown here. Can Dr. Z conclude, at  = 0.05, that the smokers have higher pulse rates than nonsmokers? Assume the samples come from a normal population. Use ...

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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