A moose claims that the average time he spends grazing per day is 6.8. Test his claim at the a=.05 level. A random sample of 234 moose shows they spent an average of 6.1 hours per day grazing. The population standard deviation is known to be 2.3 hours. What do you conclude about the claim?
Ha: mu is NOT equal 6.8.
We can use z-test. The detailed calculations are as follows: Given that the sample ...
This solution answers a question regarding population standard deviation.