A lorry travelling on the level road at 40 km/h can be stopped by its brakes in a distance 16 m. Find the speed from which it can be brought to rest in the same distance when descending a hill whose angle of slope is Sin^-1 [1/15]
The speed of the lorry = 40 km/h
= 40 x 5/18 m/s = 100/9 m/s
Distance in which it is stopped = 16 m
Using, V^2 = U^2 + 2aS to find the retardation 'a'
V = 0, U=(100/9) m/s, S = 16m, and a = ...
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