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Vehicle on sloped road: Worked out problem

A lorry travelling on the level road at 40 km/h can be stopped by its brakes in a distance 16 m. Find the speed from which it can be brought to rest in the same distance when descending a hill whose angle of slope is Sin^-1 [1/15]

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The speed of the lorry = 40 km/h

= 40 x 5/18 m/s = 100/9 m/s

Distance in which it is stopped = 16 m

Using, V^2 = U^2 + 2aS to find the retardation 'a'

V = 0, U=(100/9) m/s, S = 16m, and a = ...

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Very detail answer with easy to understand steps. It will enable you to do similar problems yourself.

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