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Stone is released from rest at top of a vertical cliff: Height of cliff, penetration force

Q1. A stone of mass 80 grams is released from rest at the top of a vertical cliff. After falling for 3 seconds, it reaches the ground and penetrates 9 cm into the ground.

Calculate:

1. the height of the cliff

2. the average force resisting the penetration

(assume gravitational acceleration g=10m/sec2)

Solution Preview

Solution. Assume that the height of the cliff is H(m)and the average force resisting the penetration is F (N). Denote the mass of the stone by m, so m=0.08kg. ...

Solution Summary

With good explanations and calculations, the problem is solved.

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