Light from a laser hits the surface of cesium. With a minimum photon energy of 2.14eV being required to remove photons. When the surface of cesium is illuminated with this light photoelectrons are emitted with a max kinetic energy of 0.76eV. Assuming that the Planck constant is 4.14x10^-15 eV Hz-1.
What would be the energy of the photons comprising the beam of light from the laser?
What color would the laser be?
The energy of photons of the incident laser beam is calculated when the kinetic energy of the emitted photoelectrons is given.