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Vectors and forces

(See attached file for full problem description with diagrams)

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? A 9.26-kg sign is hung using two cables which make an angle of 34.5 degrees with the
horizontal. Determine the weight (in Newtons) of the sign.

? Referring to the previous problem.) Determine the tension (in Newtons) in a single cable.
? A 55.9-kg sign is hung using two cables which make an angle of 26.5 degrees with the horizontal. Determine the tension (in Newtons) in a single cable.

? A 548.21-Newton sign is hung using two cables which make an angle of 26.5 degrees with the horizontal. Determine the tension (in Newtons) in a single cable.

? Determine the weight (in Newtons) of a sign which is suspended by two cables which make an angle of 29.3 degrees with the horizontal and have an individual tension of 29.7 Newtons.

? Determine the mass (in kilograms) of a sign which is suspended by two cables which make an angle of 78.1 degrees with the horizontal and have an individual tension of 342 Newtons.

? A 9.26-kg chandelier is hung from the ceiling using 5 cables which make an angle of 78.1 degrees with the horizontal. Determine the tension (in Newtons) in each individual cable.

Use the diagram below to assist in your problem solving. A 158-Newton force is being applied at an upward angle of 30.0 degrees (theta) to accelerate a 58.7-kg box across a horizontal surface. If the surface is frictionless, then determine the magnitude of the acceleration (in m/s/s).

Use the diagram below to assist in your problem solving. A 158-Newton force is being applied at an upward angle of 39 degrees (theta) to move a 58.7-kg box across a horizontal surface at a constant velocity. Determine the force of friction (in Newtons) acting upon the object.

(Referring to the previous problem.) Determine the coefficient of friction ('mu') for the above surfaces.

Use the diagram below to assist in your problem solving. A 495-Newton force is being applied at an upward angle of 30 degrees (theta) to accelerate a 59.07-kg box across a horizontal surface. If the coefficient of friction ('mu') between the surface and the object is .497, then determine the acceleration (in m/s/s).

Use the diagram below to assist in your problem solving. A 5.89-kg object is placed upon an inclined plane which has an incline angle (theta) of 39.1 degrees (theta). If the object slides down the inclined plane with a constant velocity, then what is the force of friction (in Newtons) acting upon the object?
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Solution Summary

Multiple questions relating to vectors and forces of various objects.

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