Horizontal and vertical velocity problem

Related BrainMass Solutions

• modelling projectile motion problem

  Hence, this problem can be considered as two dimensional motion (horizontal and vertical). In horizontal direction, no acceleration/zero acceleration.

• Projectile Motion: Horizontal range and time of flight.

  The horizontal component of velocity will be u*cos  and the vertical component of velocity is u*sin .

• Projectile Motion with Coefficient of Restitution

  Initial height H = 3 ft The horizontal direction will be tangential for the ground, and no force is acting in the horizontal direction (like gravity acting in the vertical direction), therefore, the horizontal velocity will not change in this problem

• Vectors and velocity: Landing speed for stone thrown from edge of a cliff

  The vectors and velocity are given. With good explanations and calculations, the problem is solved.

• Newton's laws of motion

  After that time the horizontal velocity will be: And the final vertical velocity is: The speed is the magnitude of the velocity vector and is given by: Let's hope the airbag worked......

• Cliff divers in Acapulco: Minimum horizontal velocity required to miss the rock

  Because, In horizontal direction: s = 6 m In vertical direction: h = 36 m Because initial velocity is horizontal, hence in vertical direction initial velocity = 0 h = (1/2)*g*t^2 => t = sqrt(2*h/g) = sqrt(2*36/9.8) = 2.71 sec because to

• Mechanics: Motion on Incline, Banking on Tracks, Projectile.

  As any vector is having no effect in its perpendicular direction, there will be no component of acceleration in horizontal direction and hence we can solve the problem for the horizontal and vertical motion separately and time will be linking parameter

• Velocity and Vector Problems

  (Note: You may want to use the quadratic equation for this problem.) c. Find the velocity and angle of the arrow when it lands. d. How high does the arrow get above its starting position?

• Vectors and velocity: Speed of Romeo's pebbles when they hit Juliet's window

  The vectors and velocity are calculated. With clear formulas and explanations, the problem is answered.

• Horizontal velocity and loft angles of golf clubs

  In the given problem it is assumed that 5 m/s is the actual velocity of the ball. Then obviously, the cosθ component gives the horizontal velocity. The conclusion drawn is correct. Horizontal velocity and loft angles of golf clubs are determined.