Acceleration, distance, and velocity of Car A and Car B

Car A accelerates from rest with 2m/sec^2 and Car B is moving with a constant velocity of 25 m/s. at the instant t=0.

Determine
(a) distance between the two cars at t=5 sec.
(b) time for the cars to arrive at the same location.
(c) distance of car A from the origin when they arrive at the same location.
(d) speed of car A at the instant they arrive at same location.
(e) acceleration needed for car B to come to a stop over a distance of 100 meters.

Solution Preview

a.)
velocity of car A = va = 0 + 2*t = 2t (where t is time)
velocity of car B = vb = 25 m/s
sa(t) = ut + (1/2)at^2
=> sa(t) = 0 + (1/2)*2*t^2 = t^2
sb(t) = ...

Solution Summary

The problems are solved with good explanations and detail workings.

... one fourth of the circle = Distance/Speed = 1.89 ... Average acceleration = Change in velocity/Time = 125.87/0.02 ... Direction of the average acceleration is 45O with ...

... of 15 min for the faster car the distance traveled is ... 4 : An object with an initial velocity 8m/s ... along a straight line with constant acceleration and travels ...

... to a permanent halt if its acceleration truly remains ... Numerical Problems: (Displacement, Speed and Velocity). ... old runner can cover the same distance with an ...

... Venus orbits the sun at a distance of 1.08 x 1011 m. these distances are between ... along the trajectory where the velocity and acceleration are perpendicular ...

... The angles of parallel horizontal acceleration are determined. ... But according to the turboprop, the distance is ... Of course these two distances are the same, so we ...

... 13m at ti = 0 and moves with the velocity graph shown ... a takeoff speed of 1.2m/s over a distance of 0.54 ... A. What is the flea's acceleration during the jump phase ...

... to catch the speeder and b) the distance traveled during ... in the opposite direction with a velocity of 8.0 m ... for 0.012 s, what is the average acceleration of the ...

... But according to the turboprop, the distance is: (1.16) Of course these two distances are the ... The solution examines tension, acceleration and velocity for ...

... a) Using the formula s=ut + 1/2at^2,where s is the distance from the starting point in meters, u is the velocity initially, a is acceleration in m/s^2 ...

... The expressoin for the distance traveled by this car from its ... cm/s; at the end of eight seconds its velocity is 0. What is the avearge acceleration from the ...