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Magnetic Field of Circular Coil

A small circular coil of 20 turns of wire lies in a uniform field of 0.5 T, so that the normal to the plane of the coil makes an angle of 60 degrees with the direction B (magnetic field with arrow over top). The radius of the coil is 4 cm, and it carries a current of 3 A. (a) what is the magnitude of the magnetic moment of the coil? (b) what is the magnitude of the torque exerted on the coil?

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(a)
The magnetic dipole moment of a coil is m = N?I?A, where N=20 is the number of turns, I = 3 A is the current, and A = pi?r^2 = 16pi cm^2 = 0.0016pi m^2 is the area of the coil, ...

Solution Summary

The solution examines the magnitude of the magnetic moment of the coil. The magnitude of the torque exerted on the coil is found.

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