torque required to bring to rest a rotating rod plus masses

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  When a rod is released as given, torque acting due to the gravitational force, which is acting at the CM of the rod.

• moment of inertia about center of mass and torque applied

  It shows detailed calculation of the moment of inertia of the two masses system connected by a rigid rod. It then explains how to find the torque applied to the system.

• Practice problems with rotational inertia - 7 Problems

  Moment of inertia of the body = MI of rod + MI of hoop (both about the axis of rotation) MI rod = (1/3) m L2 MI of a thin rod of mass m and length L rotating about an axis perpendicular to its length and passing through one end.

• Rotation: Moment of inertia and angular velocity.

  What is the net torque about the axle? In Nm 4.) A 1.0 kg ball and a 2.0 kg ball are connected by a 1.0-m-long rigid, massless rod. The rod is rotating cw about its center of mass at 20 rpm. What torque will bring the balls to a halt in 5.0 s?

• Rotational motion: Angular momentum and Torque

  Solved Examples: Solved Example 1: A disc has a moment of inertia of 6 kg.m2. A constant torque is applied and the disc is found to have a speed of 150 rpm 10 sec after starting from rest. Calculate the torque.

• Newtonian Mechanics Problems Involving Rotation

  The torque due to the weight of the sphere is τsphere = mg(L + r) sin θ0, where θ0 = 64O, and the torque due to the rod is τrod = mg(L/2) sin θ0.

• Angular Velocity And Acceleration

  = m*L^2 = 0.65*1.2^2 = 0.936 kg.m^2 b) Opposing force = driving force (for same velocity) = 0.020 N Hence, torque, T = F*L = 0.020*1.2 = 0.024 N.m Hence, 0.024 N.m torque is required to keep rotating the ball on rod with same speed.

• Conservation of angular momentum when a system changes configuration.

  
  If no external torque is applied to a system, its total angular momentum remains constant.
  Note 2.

• Rotation and torque

  torque for the required rotation.