300 grams of water at 0 degrees are placed in a copper container weighing 120 grams in which 35 grams of ice (at 0 degrees also). 17 grams of steam at 100 degrees are fed in and completly condensed to water. What is the temperature of the resulting mixtures.
Let us assume the final temperature of the mixture be T degree C.
Heat energy taken by 300 gm water@0 degC + 35 gm ice @0 degC + 120 gm copper container @ 0 degC
= Heat energy given by steam of 17 gm @ 100 degC
sp. heat of water sw= 1 cal/gm/C = ...
With good explanations and calculations, the problem is explained and solved.