A pendulum clock works perfectly on the Earth. It is then taken to the Moon, which has 1/6 the gravity of Earth.
a) Does it run fast or slow?
b) If the clock is started at 12:00 a.m., what will it read after one Earth day (24hrs)?
Time period T of a pendulum is given by the expression T = 2pi x Sqrt L/g ..........(1) where L = length of the pendulum, g = acceleration due to gravity. On moon value of ...
Simple problem solved simply.