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# Single slit

A long slit of infinitesimal width which is illuminated by light diffracts the light into a series of circular waves and a wave front emerges from the slit in a cylindrical wave of uniform intensity. A slit which is wider than a wavelength produces interference effects in the space downstream of the slit. The slit is assumed to behave as though it has a large number of point sources spaced evenly across the width of the slit. The analysis also simplifies if we consider light of a single wavelength.

Light incident at a given point in the space downstream of the slit is made up of contributions from each of these point sources. If the relative phases of these contributions vary by 2π or more we may expect to find minima and maxima in the diffracted light. These phase differences are caused by differences in the path lengths over which contributing rays reach the point from the slit.

We can calculate the angle at which the first minimum is obtained in the diffracted light. The light from a source is located at the top edge of the slit. This interferes destructively with a source located at the middle of the slit when the path difference between them is equal to λ/2. Furthermore, the source just below the top of the slit will interfere destructively with the source located just below the middle of the slit at the same angle. Therefore we can reason that along the entire height of the slit the condition for destructive interference for the entire slit is the same as the condition for destructive interference between two narrow slits a distance apparent that is half the width of the slit.

### Parseval Equation

How to use parseval relation to get the solution pi for part b)? Please see the attach file. A rectangular pulse is described by: [see the attached file for the equation] Show that the Fourier exponential transform is [see the attached file for the equation] This is the single-slit diffractional problem of physical op

### Determining width of slit: Example problem

A screen is placed 45.5 cm from a single slit, which is illuminated with light of wavelength 645 nm. If the distance between the second and fourth minima in the diffraction pattern is 2.93 mm, what is the width of the slit?

### Single-Slit and Diffraction

Single-slit is set to its maximum width. It is placed it in the path of the laser beam with the slit vertical and positioned so that the laser spot on the screen is as bright as possible. Compare the size and shape of the spot that would appear on the screen with that seen without the slit. The width of the slit is slo

### Single Slit Fiffraction Intensity versus Angle

The single slit diffraction pattern for a monochromatic wave of wavelength Λ incident normally on a narrow slit of width a is described in the Fraunhofer region by the intensity. I = Where θ is the deflection angle perpendicular to the incident wave front. 1. What is the value of I(θ) as θ -> 0? 2. Sketch the

### single slit diffraction pattern

See attached for exact description and figure. Suppose a single slit like the one in the figure above is 6.00 cm wide and in front of a microwave source operating at 7.5 GHz. a. Calculate the angle subtended by the first minimum in the diffraction pattern. b. What is the relative intensity I/Imax at &#952;= 15 degrees?

### Diffraction Pattern of a Single Slit

The first dark fringe in the diffraction pattern of a single slit is located at an angle of theta(sub A) = 25°. With the same light, the first dark fringe formed with another single slit is at an angle of theta(sub B) = 60°. Find the ratio W(sub A)/W(sub B) of the widths of the two slits. Really don't know where to start o

### Light diffraction/single slit

The diffraction pattern shown in Figure 28-38 is produced by passing He-Ne laser light ( lambda = 632.8 nm) through a single slit and viewing the pattern on a screen 1.00 m behind the slit. What is the width of the slit? Please see attached.

### Diffraction with sound waves

Hi. Can someone please show me how to do the following problem? Thank you. "Diffraction also occurs with sound waves. Consider 1600 Hz sound waves diffracted by a door that is 79 cm wide. What is the angle between the two first-order diffraction minima?"

### Find the angle that locates the second dark fringe when the wavelength of the light is 445nm and 655 nm.

A single slit has a width of 1.5 10-6 m and is used to form a diffraction pattern. Find the angle that locates the second dark fringe when the wavelength of the light is 445nm and 655 nm.