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Moment of inertia of a 14.0 kg sphere of radius 0.645 m

"Calculate the moment of inertia of a 14.0 kg sphere of radius 0.645 m when the axis of rotation is through its center."

I thought the equation was simply:

I = mr^2 = (14.0)(0.645)2 = 5.82 kg*m^s

but that's not the answer.

Solution This solution is FREE courtesy of BrainMass!

Because it is a sphere, every point of the sphere has different radius respect to the center. Therefore, the correct formula of moment of inertia for a sphere is I=2*M*r^2/5=2.33( kg*m^s )
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