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Speed of traveling planets using Kepler's Law

If D = 3.08 x 1011 meters and d = 1.08 x 1011 meters, and the green planet sweeps an area of 1 x 1014 m2 in a given short unit of time while traveling at 3.74 x 104 m/s, what is its speed at d to the nearest m/s?

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Solution Summary

The speed of three traveling planets is explained using Kepler's Law equations.