In the figure (see attachment) the coefficient of static friction between mass m1 and the table is 0.35, whereas the coefficient of kinetic friction is 0.25.
a) What minimum value of m1 will keep the system from starting to move? m1 = ?kg
b) What value of m1 will keep the system moving at constant speed? m1 = ?kg

The following solution provides the equations and reasoning necessary to solve both of these physics-based problems. In order to view the solution, a Word file needs to be opened.

... refer to the most appropriate one of Newton's three laws of motion. ... In both situations the inertia of motion as defined by Newton's first law of motion ...

... have been solved step by step to illustrate application of Newton's laws of motion ... he himself experiences an upward reaction force F (Newton's third law). ...

... (neglect friction and string ... Why? We have to write Newton's second law for the linear motion of each mass and then for the angular motion of the pulley. ...

... 9. A cart is rolling without friction on a platform, hooked to a hanging mass with a string which runs over a pulley, as shown ... Do not use Newton's laws. 10. ...

... Is the force exerted by friction equal to Âµkmg? yes. ...Newton's third law tells us that the air exerts an equal and opposite force (upwards) on the wings. ...

... That is because A. the kinetic coefficient of friction is larger than static coefficient B. of Newton's Third Law C. It does not take more force D ...

... h=5m. ground. Ignoring friction effects the rope mass: ... As per Newton's second law, net force on the block = Mass of the block x Acceleration. ...

... that to find the force for part (a), we simply apply Newton's second law: F = ma ... with a so-called "conservative force" we have no friction here, so ...

... The static coefficient of friction between the block and the table is 0.56 and kinetic coefficient is 0.42 ... Applying Newton's Second Law to the motion of ...