Through certain techniques, a deuterium nucleus and a tritium nucleus can be made to fuse at very low kinetic energy to form an α - particle and a neutron. Find the energy released in this reaction in MeV.
mc2 (deuterium) = 1875.613 MeV
mc2 (tritium) = 2808.921 MeV
mc2 (α - particle) = 3727.379 MeV
mc2 (neutron) = 939.565 MeV
How many fusions per second would be required to produce one (1) watt of power?
This solution explains how to determine how many fusions per second would be required to produce one watt of power.