Flux of an Electric Field
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1) When a piece of paper is held with 1 face perpendicular to a uniform electric field the flux through it is 25N.m^2/C. When the paper is turned 25 degrees with respect to the field the flux through it is:
2) The flux of the electric field(24N/C)i + (30N/C)j + (16N/C)k through a 2.0m^2 portion of the yz plane is:
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Solution Summary
This solution provides brief calculations and explanations for finding flux and plane in relation to the electric field.
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1) When a piece of paper is held with 1 face perpendicular to a uniform electric field the flux through it is 25N.m^2/C. When the paper is turned 25 degrees with ...
Purchase this Solution
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