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Flux of an Electric Field

Please show all work and show all equations used and diagrams, etc. etc. so I understand completely please.

1) When a piece of paper is held with 1 face perpendicular to a uniform electric field the flux through it is 25N.m^2/C. When the paper is turned 25 degrees with respect to the field the flux through it is:

2) The flux of the electric field(24N/C)i + (30N/C)j + (16N/C)k through a 2.0m^2 portion of the yz plane is:

Solution Preview

1) When a piece of paper is held with 1 face perpendicular to a uniform electric field the flux through it is 25N.m^2/C. When the paper is turned 25 degrees with ...

Solution Summary

This solution provides brief calculations and explanations for finding flux and plane in relation to the electric field.

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