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Gravitational potential energy of baseball thrown from roof of 120 ft tall building

A baseball is thrown from the roof of a 120 ft tall building with an initial velocity of magnitude 60 ft/s and at an angle of 37 degrees above the horizon.

1. what is the speed of the ball just before it strikes the ground using energy methods?

2. What would be the answer to the first part if the initial velocity was at angle of 37 degrees below the horizon?

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Solution:

First of all we will break the velocity into its horizontal and vertical components
Horizontal velocity = 60*cos 37 = 47.91 ...

Solution Summary

The solution explains and calculates the answers.

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