Consider an electron in an infinite well of width 0.03 nm.
Given : 1eV = 1.60218 × 10^-19 J
hbar = 1.05457 × 10^-34 J s ,

What is the ground-state energy of the electron, in electron volts? Answer in units of keV.

Part b
What is the energy of the first excited state?
Answer in units of keV.

Solution Summary

It finds the ground state energy and first excited state energy of the electron in an infinite well, respectively. The solution is detailed and was rated '5/5' by the student who originally posted the questions.

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