Consider an electron in an infinite well of width 0.03 nm.
Given : 1eV = 1.60218 × 10^-19 J
hbar = 1.05457 × 10^-34 J s ,
What is the energy of the first excited state?
Answer in units of keV.
It finds the ground state energy and first excited state energy of the electron in an infinite well, respectively. The solution is detailed and was rated '5/5' by the student who originally posted the questions.