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Conservation of energy to find height thrown of a ball up

A ball is thrown vertically upwards into the air with a speed of 8.5 m.s-1. Assuming that all of the ball's initial kinetic energy is converted into gravitational potential energy, find the amount by which the height of the ball increases (before it starts to fall again).You should assume g = 9.8 m.s-2 and give your answer to an appropriate number of significant figures and in the correct SI units.

Increase in height = ?

Solution Preview

You are given the velocity that the ball is thrown up into the air by which is V = 8.5 m/s

You should first make sure that the velocity of the ball is quote in SI units m/s if not then convert from whatever units are given to a launch velocity in m/s

The K.E is given by the equation K.E = 1/2 Mass x V(Squared) = 0.5m*V^2 {m = mass, v = velocity}

When the balls stops moving ...

Solution Summary

This solution shows how to use data on the initial launch speed of a ball thrown vertically upwards one can determine, using the principles of Kinetic Energy, Potential Energy and energy conservation to determine the maximum height that the said ball travels vertically before descending back to Earth