Please show all work and diagrams plus equations used to solve problem. Thanks!

1) Experimentor A uses a test charge qsub0 and experimentor B uses a test charge 2qsub0 to measure an electric field produced by stationary charges. A finds a field that is:

ans: The same as the field around B - WHY?

2) An isolated point charges point particle produces an electric field with magnitude E at a point 2m away from the charge. A point at which the field magnitude is E/4 is:

A) 1 m away from the charge
b) 0.5 m away from the charge
c) 2m away from the charge
d) 4 m away from the charge
e) 8 m away from the charge

3) An isolated charges point particle produces an electric field with magnitude E at a point 2m away. At a point 1 m from the particle the magnitude of the field is:

a) E
b) 2E
c) 4E
d) E/2
e) E/4

Solution Preview

1) Electrical field (kQ/r^2) is independent of test charge. You can think about in this way. Just ...

Solution Summary

The solution provides explanations and calculations for questions involving the concepts of stationary charges, point charges, and electric fields

... A) According to Superposition law, the electric field due to some distribution of charges is equal to the sum of electric fields due to each of those charges. ...

Kinetic Energy, Point Charges, Electric Field and Potential. ... The solution determines the kinetic energy, point charges, and electric field and potential. ...

Electric field discrete charge distribution. ... Please see the attached file. It provides examples involving the electric field and electric force of point charge. ...

electric field and potential of point like charges. ... In addition, the charge Q itself produces an electric field: Thus the total electric field at point P is: ...

... We get first the electric field of each charge to point P ... We will get the resultant electric field at E by getting the vector sum of the electric fields: E r ...

Angle of total electric field due to three charges. Show all workings. A charge of +10.7 micro-Coulombs is placed at the origin of a coordinate system. ...

...electric field at a point 1.5×10^−2 m from the center of the sphere. We have a spherically charged sphere. We are asked to find the electric fields inside ...

Finding the Electric Field of a Uniformly Charged Ring. ... This step-by-step solution explains how to find the electric field of a uniformly charged ring. ...