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Electron in a magnetic field - period of revolution

An electron of energy 10eV is circulating in a plane at right angles to a uniform field of strength 10^-4 Wb/m^2 (1 Gauss). Calculate the radius of the orbit of the electron and its period of revolution.

Solution Preview

Energy of the electron E = 10eV

= 10 x 1.6 x 10^-19 Joule

= 1.6 x 10^-18 J

mass m = 9.1 x 10^-31 kg

Also, E = (1/2)mv^2 ...

Solution Summary

Solution with step by step explanations and required equations.

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