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Workign with Boxes going down a belt

Ans. is given as 4.36 m/sec.
please include basic explanations
Thanks

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we will use the conservation of energy here,

the initial energy of the box E = Kinetic+ Potential

= (1/2)mv^2 + mgh

from the figure, h = 6*sin15 = 1.55

final enrgy = (1/2) m ...

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