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Collision of particles with symmetry due to interaction.

This question concerns a collision of two identical particles, A and B, each of mass m, which constitute an isolated system that is observed from an inertial frame. Assume that the particles, when sufficiently close, interact only through a potential energy function. At an instant long before the collision (when the distance between A and B is sufficiently large for the potential energy to be neglected) A has position (d, 0, -f) and velocity (0, 0, V) while B has position (-d, 0, f) and velocity (0, 0, -V), where you should assume f and V and d are positive constants.

The attachment contains the full question which goes on to ask for a description of the symmetry of the configuration. The momentum vector, total energy and angular momentum of the system.

There is a further question where by I need to determine which of three, given configurations, is the correct one using the principle of relativity and conservation laws.


Solution Summary

The solutions deals with the collision while the particles interacts at large distances by conserving momentum and energy. This also discuss the position during the interaction.