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Physical pendulums

A thin uniform ring, placed on a knife edge pivot executes SHM period 'Tr'.
The same ring is cut, then straightened to form a bar, which executes SHM with a period 'Tb'.
Find the ratio of periods, Tb/Tr.


Solution Preview

Step1. Recall moments of inertia as follows:
Thin uniform ring about its c.m. axis (at center): (1) Io ...

Solution Summary

Compare period of ring to that of bar.