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In the hydraulic lift the red piston has a cross-sectional area of 0.69 m2 and the green piston a cross-sectional area of 0.06 m2 and the force F1 = 176 N. What weight to the nearest newton can this configuration lift?

If the green piston is depressed 0.67 meters, how far up would the red piston move to the nearest thousandth of a meter?

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This Solution contains calculations to aid you in understanding the Solution to these questions. The fluids cross-sectional area is determined.

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In the hydraulic lift the red piston has a cross-sectional area S2 of 0.69 m2 and the green piston a cross-sectional area S1 of 0.06 m2 and the force F1 = 176 N. What weight to the nearest Newton can this configuration ...

Solution provided by:
Changping Wang, MA
Education
  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
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  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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