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Variable refractive index

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Light is passing through a 4 cm thick slab of special doped glass. The index of refraction varies smoothly n=2/sqrt(h) where "h" is the distance from one surface of the slab measured in centimeters. Use Fermat's principle to find the equation for the path of a light ray going from the high index side of the slab to low index side of the slab.

(I forgot to add the last part of the problem, "to the low index...". I am not sure if this is helpful, but this is all the information I was given for this problem. If a boundary condition is necessary, I think it would be alright to assume a condition and make note of it).

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Solution Summary

Path traced by light in a medium of varying refractive index, is derived.

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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