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Electronics_A charging capacitor

In the circuit below how long does it take for the current to drop to 1 uA when the switch is moved from position A to B. (Assume that it has been at A for a long time)

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Sum of voltage around a loop = 0 (given in your equation chart)

Therefore,

V2 = I R + Q /C

During the charging of the capacitor, initially the capacitor did not have any charge. Current in the circuit is maximum. (Imax = V2 /R since Q = 0 at t=0)

With time, charge builds up in the ...

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