Hi. Can someone please walk me through how to do the following problem?
Two capacitors, one 7.5 micro-F and the other 15 micro-F are connected in a series across a 12-V battery. (a) Find the equivalent capacitance of the two capacitors. (b) Which capacitor stores more charge. Explain. (c) Find the charge stored on each capacitor.
When two capacitors are connected in series the equivalent capacitance is given by,
1/C_eq = 1/c1 + 1/c2
C_eq = c1*c2/[c1+c2]
Thus here, C_eq = 7.5*10^-6*15*10^-6/[7.5+15]*10^-6
= 5*10^-6 Farad = 5 microfarad ...
The answer is given step-by-step equationally.