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Physics: Application of the principle of conservation of energy

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Using the principle of conservation of energy:

(a) determine the speed of 3.00kg object just as the 5.00kg object hits the ground.
(b) find the maximum height to which the 3kg object rises.
(c) How will this mass as it descends rise the mass up as v=0 (m1 and m2 both have a v=0) (solve for y)

I have the answers to (a) 4.43m/s (b) 5m (I need (c) and show me how to get it)

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Solution Summary

The application of the principle of conservation of energy are given. The maximum height of an object is found. With a diagram and a good explanation, part c is fully explained.

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m2= 3.00kg, m1 = 5.00kg. h=4 Two objects are connected by a light string passing over a light frictionless pulley. The object of 5.00kg mass is released from rest. Using the principle of conservation of energy. (a) determine the speed of 3.00kg object just as the 5.00kg object hits ...

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