A 3.5 kg block is put on top of a 6 kg block. To cause the top block to slip on the bottom one, while the bottom one is held fixed, a horizontal force of at least 15.4 N must be applied to the top block. The assembly of blocks is now placed on a horizontal frictionless table.

Please explain how to:

1. Find the magnitude of the max. horizontal force that can be applied to the lower block so that the blocks will move together.

RESPONSE:
Physics notes:
Note 1. Newton's second law is applicable to either block or the whole system.
Note 2. When the lower block, M2, is accelerated forward, the friction force exerted on the bottom of the upper block, M1, is forward.
Note 3. The only external ...

Solution Summary

The solution includes calculations for finding the magnitude of horizontal force and acceleration in system where two blocks are stacked on top of one another.

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