An arrow is accidentally shot into the air. The formula y = - 14x2 + 56x + 18 models the arrow's height above the ground, y, in feet, x seconds after it was released. When does the arrow reach its maximum height? What is that height?

Maximum height is solved by finding the vertex of a parabola. The solution is detailed and well presented. The response was given a rating of "5/5" by the student who originally posted the question.

... c) Find the maximum height of the pebble. ... 3 (b) s(2) = -16(2^2) + 80(2) + 3 = 99 ft (c) Maximum height is the y- coordinate of the vertex of the parabola. ...

... It also explains the concept of finding maximum nad minimum ... the graph of parabola opens upwards then parabola has a ... What are the coordinates of the vertex in (x ...

... has a minimum value of -9 at x = 1. The graph (parabola) opens upwards ... Answer: The vertex is (1, -9 ... web-based graphing utility to plot the points found in part a ...

... b. Find the t-coordinate and S-coordinate of the vertex of the graph of this quadratic function. ... (a) The graph is a parabola with vertex at (-b/2a, (4ac ...

... helpful to express the quadratic in its vertex form ... solutions of a quadratic solution can be found from its ... at the points where the graph (parabola) crosses (or ...

... (3) Find the area ... Two of the vertices of the rectangle will lie on the x-axis and the others ... Let (x, y ) be the vertex that lies in the ﬁrst quadrant on the ...

... The vertex points are the extreme points on the major axis. ... we can conclude that a<b and the vertices are: (0 ... x2 y2 + =1 5. Find the eccentricity of the ellipse ...