Working with a sinusoidal function
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This question concerns the function
y/3 = 3+ 4sin [3x+ pi ]
Where x is measured in radians.
(1) Choose the one option which gives the value of the function when x= pi/2
(2) Choose the one option which gives the period of the function.
Options for questions 1 and 2.
A 1
B. 2
C. 3
D. 4
E. pi/3
F. 2pi/3
G. pi
H. 3pi
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Solution Summary
A thorough answer with all mathematical steps. The sinusoidal function values are examined. The period of the functions are determined.
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(1)
our function is
y/3 = 3+ 4sin [3x+ pi ]
when x=pi/2
We have, 3x + pi = (3pi/2)+pi = 5pi/2 = (2pi + pi/2)
Sin function repeats itself when we add 2pi to it
Hence Sin(2pi + pi/2)= Sin(pi/2) = 1
Substitute this value back to the given function and find the value of y.
y/3 = 3+ 4sin ...
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