Trigonometric inverse function

Related BrainMass Solutions

• Evaluate integral of inverse trigonometric function

  So, = Note 1: 2. 0 ≤s≤3√2∕4, then 0 ≤u≤√2∕2 This shows how to find the integral of a given inverse trigonometric function.

• Inverse Trigonometric Function

  195086 Inverse Trigonometric Function Evaluate the following inverse trigonometric expressions: 1. sec (3 arctan 3/4) 2. sin (4 arccos 1/2) 3. cos (2 arcsin 3/7) 4. cos (3 arccos 2/3) (1) sec(3 arctan(3/4)) = sec(3 * 36.8699) = sec(110.6096

• complex number based inverse trigonometric function

  Tony The solution provides detailed explanation how to simplify the complex number based inverse trigonometric function.

• Trigonometric Functions : Explain sine, cosine, tangent, cotangent functions and inverses.

  Inverse Trigonometric Functions The arcsin function We restrict the domain of the sine function to [-pi/2 , pi/2]. Now this restriction is invertible because each image value in [-1,1] has just one origin in [-pi/2 , pi/2].

• Derivative of inverse trigonometric function

  62649 Derivative of inverse trig function How do you solve: y= sec‾¹ 5s Please see the attached file. This shows how to find the derivative of a given inverse trigonometric function.

• Plane trigonometry for inverse functions

  : This shows how to write the inverse of trigonometric functions and solve several plane trigonometry problems.

• Derivative of inverse trigonometric function.

  62648 Derivatives of inverse trig functions How do you solve: y= cos‾1 (1∕x) Please see the attached file. This shows how to find the derivative of a given inverse trigonometric function.

• Evaluating, Solving and Continuity of Trigonometric Expressions, Equations and Functions (10 Problems)

  (sin(x))^2 = 1/16 x = ______ Your final answer is not suppose to contain any trigonometric or inverse trigonometric functions. PART 2: Match expressions from Group A to group B and show reasoning.

• Trigonometry : Domain and Range

  In order for cos x to have inverse, we merely restrict the domain of cos x to [0, pi]. i.e. g(x) = cos(x) where x is in [0 , pi] Check that the range of g(x) is [-1,1]. See that this function is a one-to-one function.