Solving Trigonometric Equations
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Approximate the solution of the equation in the interval [0,2pi]. If possible find the exact solutions algebraically. (sin 2x + cos 2x)^2 = 1
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A trigonometric equation is solved. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.
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Please see the solution to your problem in the attached word file
'Solution_trignometry_01.doc'.
Here the square bracket means the closed interval. So I have given the solution according to the closed interval. In case, if the problem shows that its an open interval and square bracket is not there in the problem of your book, then the solution will be different as given after the solution with the closed interval, in the word document. So you will find the solution for both type of intervals ...
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