1. Solve csc^2θ - 2 cot θ = 4 for solutions over the interval [0°, 360°]. Express approximate solutions to the nearest tenth of a degree. Could you please show me step by step to see how to get the correct answer? The correct answers are (18.4°, 135°, 198.4°, 315°)
cosec^2(θ) - 2 cot(θ) = 4
=> 1 + cot^2(θ) - 2cot(θ) = 4
=> cot^2(θ) - 2cot(θ) - 3 = 0
=> cot^2(θ) - 3cot(θ) + ...
This shows how to solve a trigonometric equation over a given interval.